问题标题：
求lim(x→0)〔1-cos2x-(tan^2)X〕/xsinx过程谢谢
问题描述：
求lim(x→0)〔1-cos2x-(tan^2)X〕/xsinx过程谢谢
侯平回答：
lim(x→0)〔1-cos2x-(tan^2)X〕/xsinx
=lim(x→0)〔1-cos2x-(tan^2)X〕/x^2
=lim(x→0)〔1-cos2x〕/x^2-lim(x→0)(tan^2)X/x^2
=lim(x→0)〔(2x)^2/2〕/x^2-lim(x→0)(x^2)/x^2
=2-1
=1
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