问题标题:
【用※定义一种新运算,如果x※y=1/xy+1/(x+1)(y+1),求2※(3※1)的值】
问题描述:

用※定义一种新运算,如果x※y=1/xy+1/(x+1)(y+1),求2※(3※1)的值

高洪亮回答:
  2※(3※1)   =2※[1/3*1+1/(3+1)(1+1)]   =2※(1/3+1/8)   =2※(8/24+3/24)   =2※11/24   =1/(2*11/24)+1/(1+2)*(1+11/24)   =1/(11/12)+1/(35/8)   =12/11+8/35   =420/385+88/385   =472/385
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