问题标题:
(1)I额=P额/U额代入数值得:I额=880W/220V=4A(2)R=U额/I额代入数值得:R=220V/4A=55Ω(3)10min电热水壶消耗的电能:W=P额t代入数值得:W=880W×10×60s=5.28×105J(或约0.15kw·h)答
问题描述:
(1)I额=P额/U额
代入数值得:I额=880W/220V=4A
(2)R=U额/I额
代入数值得:R=220V/4A=55Ω
(3)10min电热水壶消耗的电能:W=P额t
代入数值得:W=880W×10×60s=5.28×105J(或约0.15kw·h)
答:电热水壶的额定电流是4A;电热水壶的电阻是55Ω;电热水壶消耗的电能5.28×105J.
程雪飞回答:
哦
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