问题标题：
一道分式数学题,先化简再求值(1x+1)-(x+3/x^2-1)/(x^2+4x+3/x^2-2x+1),其中x=－3
问题描述：
一道分式数学题,先化简再求值
(1x+1)-(x+3/x^2-1)/(x^2+4x+3/x^2-2x+1),其中x=－3
崔大付回答：
(1x+1)-(x+3/x^2-1)/(x^2+4x+3/x^2-2x+1),
=1/(x+1)-(x+3)/(x+1)(x-1)*(x-1)^2/(x+1)(x+3)
=1/(x+1)-(x-1)/(x+1)^2
=(x+1-x+1)/(x+1)^2
=2/(x+1)^2
=2/(-3+1)^2
=1/2
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