问题标题:
数学题之53用递等式计算.1.15/4*12/5-12/5/120%2.100.1-(2.625+0.425)*303.99/{23/4-(9/5+21/5*2/7)}4.(1/4+3/8)/(1-3/10)
问题描述:
数学题之53
用递等式计算.
1.15/4*12/5-12/5/120%2.100.1-(2.625+0.425)*30
3.99/{23/4-(9/5+21/5*2/7)}4.(1/4+3/8)/(1-3/10)
李庆回答:
用递等式计算.1.15/4*12/5-12/5/120%=9-2=72.100.1-(2.625+0.425)*30=100.1-3.05*30=100.1-91.5=8.63.99/{23/4-(9/5+21/5*2/7)}=99/[23/4-3]=99/11/4]=364.(1/4+3/8)/(1-3/10)=5/8/(7/10)=25/2...
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