问题标题：
【7m(4m^2×p)^2/7m^2[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y(2x+y+z)(2x-y-z)(2x-y-3)^2(x+y+1)(x+y-1)】
问题描述：
7m(4m^2×p)^2/7m^2[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y(2x+y+z)(2x-y-z)(2x-y-3)^2(x+y+1)(x+y-1)
邓述珍回答：
1、7m(4m^2·p)^2=7m*4^2*(m^2)^2*p^2=7m*4^2*m^4*p^2=7*16m*m^4*p^2=112m^5*p^2所以7m(4m^2·p)^2÷7m^2=112m^5*p^2÷7m^2=16m^3p^2
2、[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)={x[xy(xy-1)]-y[x²(1-xy)]}/(3x²y)=[x²y(xy-1)-yx²(1-xy)]/(3x²y)=[x²y(xy-1)+yx²(xy-1)]/(3x²y)=[x²y(xy-1)+x²y(xy-1)]/(3x²y)=[2x²y(xy-1)]/(3x²y)=[2(xy-1)]/3
3、(2x+y+z)(2x-y-z)=(2x+y+z)[2x-(y+z)]=(2x)^2-(y+z)^2=4x^2-(y^2+2yz+z^2)=4x^2-y^2-2yz-z^2
高焕春回答：
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邓述珍回答：
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高焕春回答：
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邓述珍回答：
ԭʽ=[(x+y)+1][(x+y)-1]=(x+y)²-1²=x²+2xy+y²-1(zx-y-3)^2=(zx-y)^2-6(2x-y)+9=zx^2-4xy+y^2-12x+6y+9
高焕春回答：
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邓述珍回答：
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