问题标题：
【高一数学sin(540-X)1cos(360-X)—————*——-----------------*-----------tan(900-X)tan(450-X)*tan(810-X)sin(-X)化简上式,求过程】
问题描述：
高一数学
sin(540-X)1cos(360-X)
—————*——-----------------*-----------
tan(900-X)tan(450-X)*tan(810-X)sin(-X)
化简上式,求过程
郭兰英回答：
少了个"度"
sin(540-x)cos(360-x)/tan(900-x)tan(450-x)tan(810-x)sin(-x)
=sin(180-x)cos(-x)/tan(180-x)tan(90-x)tan(90-x)sin(-x)
=-sin(x)cos(x)tan(x)tan(x)cos(180-x)/sin(180-x)sin(x)
=cos^2(x)tan^2(x)/sin(x)
=sinx
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