问题标题：
tanπ/12-1/tanπ/12=
问题描述：
tanπ/12-1/tanπ/12=
陈黎飞回答：
=(sinπ/12)/(cosπ/12)-(cosπ/12)/(sinπ/12)=（sin²π/12-cos²π/12）/(sinπ/12*cosπ/12)=2*（sin²π/12-cos²π/12）/(sinπ/6)=2*(-cosπ/6)/(sinπ/6)=-2/(tanπ/6)=-2√3(公式：tanA=si...
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