问题标题:
因式分解(x-1)(x+5)(x+3)+12
问题描述:
因式分解(x-1)(x+5)(x+3)+12
李瑞波回答:
(x^2-1)(x+3)(x+5)+12=(x+1)(x-1)(x+3)(x+5)+12=[(x-1)(x+5)][(x+3)(x+1)]+12=(x^2+4x-5)(x^2+4x+3)+12=[(x^2+4x-1)-4][(x^2+4x-1)+4]+12=(x^2+4x-1)^2-16+12=(x^2+4x-1)^2-4=(x^2+4x-1+2)(x^2+4x-1-2)=(x^2...
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