问题标题:
因式分解法解下列方程1.X²-7X+6=02.(5X-1)²=3(5X-1)3.(2X-5)²-(X+4)²=0因式分解法解下列方程1.X²-7X+6=02.(5X-1)²=3(5X-1)3.(2X-5)²-(X+4)²=0
问题描述:
因式分解法解下列方程1.X²-7X+6=02.(5X-1)²=3(5X-1)3.(2X-5)²-(X+4)²=0
因式分解法解下列方程
1.X²-7X+6=0
2.(5X-1)²=3(5X-1)
3.(2X-5)²-(X+4)²=0
石海彬回答:
1.X²-7X+6=0
(X-6)(X-1)=0
X1=6X2=1
2.(5X-1)²=3(5X-1)
(5X-1)²-3(5X-1)=0
(5X-1)(5X-1-3)=0
X1=1/5X2=4/5
3.(2X-5)²-(X+4)²=0
4X²-20X+25-X²-8X-16=0
3X²-28X+9=0
(3X-1)(X-9)=0
X1=1/3X2=9
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