问题标题：
Amajor-leaguepitchercanthrowabaseballinexcessof41.0m/s.Ifaballisthrownhorizontallyatthisspeed,howmuchwillitdropbythetimeitreachesacatcherwhois17.0mawayfromthepointofrelease?
问题描述：
Amajor-leaguepitchercanthrowabaseballinexcessof41.0m/s.Ifaballisthrownhorizontallyatthisspeed,howmuchwillitdropbythetimeitreachesacatcherwhois17.0mawayfromthepointofrelease?
陆亮回答：
这个问题说的是一个职业联赛的棒球投手能以41米每秒的速度抛出棒球,当他水平的将球抛出到离他17米远的接手时,这个球下降的高度是多少?
球运行的时间t＝17/41,球下降的高度h＝1/2*g*t^2=1/2*10*(17/41)^2,用计算器算出来就行了
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