问题标题:
∫(4x+3)/(x-2)^3dx求有理函数积分?
问题描述:
∫(4x+3)/(x-2)^3dx求有理函数积分?
何志军回答:
∫(4x+3)/(x-2)^3dx=∫(4x-8+11)/(x-2)^3dx=∫(4x-8)/(x-2)^3dx+∫11/(x-2)^3dx
=∫4/(x-2)^2dx+∫11/(x-2)^3dx
=-4/(x-2)-11/2(x-2)^2+C
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