问题标题:
【若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,】
问题描述:
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值
蒋滋康回答:
x(x-1)-(x²-y)=-6
得:x²-x-x²+y=-6
解得:x-y=6
所以(x-y)²=6²
x²-2xy+y²=36
所以x²+y²=36+2xy
(x²+y²)/2-xy
=(36+2xy)/2-xy
=18+xy-xy
=18
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