问题标题:
【若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,】
问题描述:

若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值

若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值

若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值

若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值

若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值

若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值

蒋滋康回答:
  x(x-1)-(x²-y)=-6   得:x²-x-x²+y=-6   解得:x-y=6   所以(x-y)²=6²   x²-2xy+y²=36   所以x²+y²=36+2xy   (x²+y²)/2-xy   =(36+2xy)/2-xy   =18+xy-xy   =18
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