问题标题:
化简根号2sin(π/3-x)+根号6cos(π/3-x)
问题描述:

化简根号2sin(π/3-x)+根号6cos(π/3-x)

陈振庆回答:
  根号2sin(π/3-x)+根号6cos(π/3-x)   =2√2*[sin(π/3-x)(1/2)+(√3/2)cos(π/3-x)]   =2√2*[sin(π/3-x)*cos(π/3)+cos(π/3-x)*sin(π/3)]   =2√2*sin[(π/3-x)+π/3]   =2√2*sin(2π/3-x)
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