问题标题:
初二数学题,分解因式(x+1)(x+3)(x+5)(x+7)+16,快点啦
问题描述:

初二数学题,分解因式(x+1)(x+3)(x+5)(x+7)+16,快点啦

童晓艳回答:
  =[(x+1)(x+7)][(x+3)(x+5)]+16   =[(x²+8x)+7][(x²+8x)+15]+16   =(x²+8x)²+22(x²+8x)+105+16   =(x²+8x)²+22(x²+8x)+121   =[(x²+8x)+11]²   =(x²+8x+11)²
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