问题标题:
2sin130°+sin100°(1+√3tan190°)/√1+cos10°
问题描述:
2sin130°+sin100°(1+√3tan190°)/√1+cos10°
秦世引回答:
[2sin130°+sin100°(1+√3*tan190°)]/√(1+cos10°)=[2sin50°+sin80°(1+√3*tan10°)]/√(1+cos10°)=[2sin50°+cos10°(1+√3*(sin10°/cos10°))]/√(1+cos10°)=[2sin50°+(cos10°+√3*sin10°)]/√(1+cos10...
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