和这个问题的手工计算计算量可不小呀我也不想花费那个冤枉时间 　　下面我使用Matlab帮你计算下吧很简单的 　　程序如下： 　　%bydynamic 　　%2009.3.5 　　>>solve('t^4=6*t^2-t-12')%下面是解析解够复杂的吧,恩接着后面我将它转化为数值解了你可以看看但是没有实根哦 　　ans= 　　1/4*2^(1/2)*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)+1/4*(-(-32*(708+4*i*671^(1/2))^(1/3)*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)+2*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)*(708+4*i*671^(1/2))^(2/3)+160*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)+8*2^(1/2)*(708+4*i*671^(1/2))^(1/3))/(708+4*i*671^(1/2))^(1/3)/((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2))^(1/2) 　　1/4*2^(1/2)*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)-1/4*(-(-32*(708+4*i*671^(1/2))^(1/3)*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)+2*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)*(708+4*i*671^(1/2))^(2/3)+160*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)+8*2^(1/2)*(708+4*i*671^(1/2))^(1/3))/(708+4*i*671^(1/2))^(1/3)/((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2))^(1/2) 　　-1/4*2^(1/2)*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)+1/4*(-(-32*(708+4*i*671^(1/2))^(1/3)*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)+2*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)*(708+4*i*671^(1/2))^(2/3)+160*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)-8*2^(1/2)*(708+4*i*671^(1/2))^(1/3))/(708+4*i*671^(1/2))^(1/3)/((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2))^(1/2) 　　-1/4*2^(1/2)*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)-1/4*(-(-32*(708+4*i*671^(1/2))^(1/3)*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)+2*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)*(708+4*i*671^(1/2))^(2/3)+160*((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2)-8*2^(1/2)*(708+4*i*671^(1/2))^(1/3))/(708+4*i*671^(1/2))^(1/3)/((8*(708+4*i*671^(1/2))^(1/3)+(708+4*i*671^(1/2))^(2/3)+80)/(708+4*i*671^(1/2))^(1/3))^(1/2))^(1/2) 　　>>vpa(ans,5) 　　ans= 　　1.7982-.61035*i 　　1.7982+.61035*i 　　-1.7982-.30740*i 　　-1.7982+.30740*i 　　>>roots([10-6112])%当然熟悉Matlab的人,可以使用这个命令,求得的结果是一样的 　　ans= 　　1.7982+0.6103i 　　1.7982-0.6103i 　　-1.7982+0.3073i