问题标题:
(2014•河池一模)已知函数f(x)=xx+1,若数列{an}(n∈N*)满足:a1=1,an+1=f(an)(1)设bn=1an,求证数列{bn}是等差数列;(2)求数列{an}的通项公式;(3)设数列{cn}满足:cn=2nan,求数列{cn
问题描述:

(2014•河池一模)已知函数f(x)=xx+1,若数列{an}(n∈N*)满足:a1=1,an+1=f(an)

(1)设bn=1an,求证数列{bn}是等差数列;

(2)求数列{an}的通项公式;

(3)设数列{cn}满足:cn=2nan,求数列{cn}的前n项的和Sn.

黄泽贵回答:
  (1)证明:∵数f(x)=xx+1
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