问题标题:
计算:1/(n+1)+1/(n+1)(n+2)+1/(n+2)(n+3)+1/(n+3)(n+4)+1/(n+5)(n+6)+.+1/(n+9)(n+10)
问题描述:

计算:1/(n+1)+1/(n+1)(n+2)+1/(n+2)(n+3)+1/(n+3)(n+4)+1/(n+5)(n+6)+.+1/(n+9)(n+10)

贾广余回答:
  原式=1/(n+1)+1/(n+1)-1/(n+2)+1/(n+2)-1/(n+3)+.+1/(n+9)-1/(n+10)=2/(n+1)+1/(n+10)
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